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mysql_query help
<div id="col-two"> <div class="boxed"> <h2 class="title">SUBMIT</h2> <div class="content"> <p> <? $A = $_POST['Artist']; $B = $_POST['Album']; $C = $_POST['Song']; $D = $_POST['GuitarX']; $E = $_POST['GuitarH']; $F = $_POST['GuitarM']; $G = $_POST['GuitarE']; $H =...- xsystemx
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- Forum: Scripts, 3rd Party Apps, and Programming
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help
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>FOFDB</title> <link href="default.css" rel="stylesheet"...- xsystemx
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- Forum: Scripts, 3rd Party Apps, and Programming
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form to mysql
Yes that is exatyl wat i want, if its checked an INT, will be inserted, 1 if its checked and 0 if not, i will fix up my code with your suggesions and pust the resulting code i you need a preview fofdb.x10hosting.com/Submit.php i am not sure exatly on how to do the verifyMe thing u suggested...- xsystemx
- Post #4
- Forum: Scripts, 3rd Party Apps, and Programming
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form to mysql
<script language='javascript'> function verifyMe(){ var msg=''; if(document.getElementById('Artist').value==''){ msg+='- Artist\n\n';} if(document.getElementById('Album').value==''){ msg+='- Album\n\n';} if(document.getElementById('Song').value==''){ msg+='- Song\n\n';}...- xsystemx
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- Replies: 4
- Forum: Scripts, 3rd Party Apps, and Programming