Math problem :P

galaxyAbstractor

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An oildrop with the volume 0.1 cubiccentimetres spread across the water making a 40 squaremetre large circular area with the same thickness. How thick is the layer of oil?

Lol just want to see how many gets the right answer :p :biggrin:
 

vievie

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My answer is 0.00000025m in thickness. Assuming the layer of oil is a cylinderical shape =P

BTW, remember conversion of cm^2 to m^2 is not a factor of 100, but 10000 ;)
 
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kirtik

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Lol? I just did this the other day in my A level Physics class.

The layer is one molecule of oil thick.

4/3 Pi R^3 = sphere
Pi r^2 h = cylinder

Due to the conservation of volume rule,

4/3 Pi R^2 = Pi r^2 h

Rearrange formula to get:

h= (4/3 Pi R^3) / (Pi r^2)

Substitute known values...

0.1 cc = 1.0 x 10^-7 m^3

40m^2 = Pi r^2

Therefore, h = (1 x 10^-7) / (40)

h = 0.0000000175m.
 

leafypiggy

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i think that h = 1.39299399492883848939949939 where the 39299399492883848939949939 repeats. JK. lol. I'm only in algebra 1. lol'


your answers make sense tho.
 
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galaxyAbstractor

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My answer is 0.00000025m in thickness. Assuming the layer of oil is a cylinderical shape =P

BTW, remember conversion of cm^2 to m^2 is not a factor of 100, but 10000 ;)

Right!

Took me 15 minutes to figure out and I did forgot some things so here is how I did (I bet it isn't the best way):

40/3.14 = 12.73.
*sqr*12.73 = 3.57.

The radious of the circle is 3.57 Metres.

3.57 Metres = 357 Centimetres

357^2*3.14 = 400 000 squarecentimeters

400 000 * 0.00000025 = 0.1 cubiccentimetres

Thickness 0.00000025 cubiccentimetres = 2.5 * 10^-9
 
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